Earlier today I had to spend a whole 20 minutes coming up with this function. It’s like a modulo function, but instead of looping back to zero every cycle, it transitions back down to zero. It cycles every 2(n-1) elements. There’s probably a proper name for it, but I can’t figure it out.
In case anyone else would rather google it than spend time figuring it out, here it is:
def ping_pong_mod(i, n):
cycle = 2 * (n - 1)
i = i % cycle
if i >= n:
return cycle - i
return i
I hope this is helpful to a fellow lazy person in the future.
Hello, I am a lazy person and you saved me a lot of trouble, so thank you!
In my case I wanted the “book-ends” to be repeated, like this:
p4(x) = 0, 1, 2, 3, 3, 2, 1, 0, 0, 1, 2…
so I had to modify it slightly:
function ping_pong_mod(i, n){
let cycle = 2 * n
i = i % cycle
if (i >= n)
return cycle – 1 – i
return i
}